약수의 개수와 덧셈

Java

class Solution {
    public int solution(int left, int right) {
        int answer = 0;
        
        for(int number = left; number <= right; number++){
            int count = 0;
            for(int i = 1; i <= number; i++){
                if(number % i == 0)     count++;
            }
            if (count % 2 == 0)     answer += number;
            else                    answer -= number;
        }
        return answer;
    }
}

 

Python

import math
def solution(left, right):
    answer = 0
    for number in range(left, right + 1):
        count = 0
        for i in range(1, number + 1):
            if number % i == 0:
                count += 1
        if count % 2 == 0:
            answer += number
        else:
            answer -= number
    return answer

 

Go

func solution(left int, right int) (answer int) {
    answer = 0
    
    for number := left; number <= right; number++ {
        count := 0
        for i := 1; i <= number; i++ {
            if number % i == 0 {
                count++
            }
        }
        
        if count % 2 == 0 {
            answer += number
        } else {
            answer -= number
        }
    }
    
    return
}